Given that electron charge is really so brief, these types of legislation work very well to explain electrostatics getting regular products

Given that electron charge is really so brief, these types of legislation work very well to explain electrostatics getting regular products

ANSWER: The principles you learn such as the that your quote apply merely in the event that charges can be thought of as an ongoing fluid that can spread in itself from people surface, no matter how highest, and have now no occurrence. Definitely, a situation as you define, that have 5 a lot of electrons is actually no way like a fluid and that i create guess that everything from 5-0 to 0-5 could be the shipping more than a period of time. Theoretically, the 5 electrons create arrange themselves to ensure for each and every is actually given that at a distance throughout the most other 4 as possible, however, there would not be another for example shipment.

QUESTION: Could it be you can easily so you’re able to suspend an enthusiastic electron through electrostatic levitation in a good uniform magnetized career? If in case new voltage are diminished sufficient so that the electrostatic push into electron was below the brand new force because of new electron’s pounds manage the latest electron after that sense a beneficial ‘fall’ due so you can the law of gravity?

I am inquiring this because I am thinking when the position an excellent positron in an excellent consistent magnetic industry (within the a vacuum) and you can reducing the voltage to help you a very small worth to make certain that brand new electrostatic push is lower than the weight do bring about a positron so you can and additionally experience a good ‘fall’. And in case they performed experience a fall it may be determined when it carry out slip right up or down.

From the inertial size I mean the latest ratio of the force you apply at it split up by the their velocity, to put it differently its effectiveness getting accelerated

I’m 17 years old and also in the uk about to research physics in the university inside the sep and you can was just curious about this as one of the topics in 2010 was electricity phenomena and you can i talked about millikan’s petroleum get rid of check out and that checked an equivalent form of suspension in the event that electrostatic push and you will force due to the law of gravity was basically balanced.

Now, we know in order to extraordinary reliability your inertial bulk of an excellent positron is equivalent to new inertial mass off an electron

ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board https://datingranking.net/sports-dating/! Keep asking those hard and interesting questions, though, and good luck with your university studies.